Find x in the following

Find x in the following 900 50 (v) 1300 (vi) ZBDC = LBAC= 300 [L in the same segment). In LBCD, thesum of the angles is 10.

Dear Student,
(iv) BOC=360°-120°+90°=360°-210°=150°BOC is the angle subtended by an arc BC at the center.And we know that angle subtended by an arc at the center is double the angle subtended at any point on the circle.So, BOC=2BAC2BAC=150°BAC=75°Therefore the value of x is 75°v) We know that angle subtended at any point on circle by a diameter is 90°so, ACB=DBC=90°Considering ACB we have;CAB+ACB+ABC=180°50°+90°+ABC=180°ABC=180°-50°+90°=40°DBC=90°x+ABC=90°x+40°=90°x=90°-40°=50°
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