For a mass M kept at the centre of a cube of side ‘a’, the flux of gravitational field passing through its sides is 4π GM. how ??

The gravitational field at the centre of a cube ofside a is given by,               E=GMa2Now constructing Gaussian surface around the cube of radius a, we get,              φ=E×dS=E×4πa2=GMa2×4πa2=4π×GM.

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