For how many grams of CO2 gas, the product of pressure and volume will be equal to 40R lit-atm at 127??

Dear Student,
According to the question, PV = 40R L.atm
                                            T = 127^oC = (127 + 273) K = 400 K
Applying ideal gas equation, PV = nRT
                                             40R = nR(400)
                                             n = 0.1 moles
mass of CO₂ = 0.1 mol $\times$ 44 gmol^-1 = 4.4 g

Regards