For the equilibrium SO3 (g) = SO2 (g) + 1/2 O2 (g), the molar mass at equilibrium was observed to be 60, then the degree of dissociation of SO3 would be? Answer is 0.66 Share with your friends Share 8 Vinod Sai answered this 2so3 2so2+o2 -6 View Full Answer Guhapriya answered this This is the exact answer -10 Aditi Dwivedi answered this Give answer -10 Shivam answered this Which formula is thisplease tell me i have a doubt 6 Anusha Jain answered this 0.66 -9 Aishani Shaw answered this SO3=SO2+1/2O2 n=1+(1/2)=3/2 Mt=molar mass of SO3=80 Degree of dissociation = Mt-Mo/(n-1)Mo =80-60/(3/2-1)×60=0.66=66% 6 Aishani Shaw answered this This is the answer 11 Nikhil answered this 2/3=0.666.. 6