For the function F,given by f(x)=x2-6x+8,prove that f '(5)-3f '(2)=f '(8)
Given: f(x)=x^2-6x+8
To Prove : f '(5)-3f '(2)=f '(8)
f '(x) is a notation generally used for d(f(x))/dx
Therefore f '(x)=d(f(x))/dx=2x-6. [As d(x^m)/DX= mx^(m-1)]
Substituting for x,
f '(5)=2(5)-6=4
f '(2)=2(2)-6=-2
f '(8)=2(8)-6=10=RHS
Now,
LHS=f '(5)-3f '(2)= 4 - 3(-2)=4+6=10=RHS
Hence Proved.