# for the reaction 3A(g)+B(g)=2C(g) at a given temperature,Kc=9.0 . what must be the volume of the flask, if a mixture of 2.0 mole each of A,B and C exist in equilibrium?

Given :
Kc​ = 9.0
2 moles each of A, B, C

​To find :
volume, V = ?

Solution :
For the reaction ,

The equilibrium constant ,Kc$\frac{\left[C{\right]}^{2}}{\left[A{\right]}^{3}\left[B\right]}$

concentration =
where , concentration [C] = [A] =[B] = $\frac{2}{V}$ mol L-1

V = 6 L
​Volume of the flask is 6 L

• 93
What are you looking for?