For the reaction equilibrium, 2 NOBr(g) 2 NO(g) + Br2(g) . If PBr2 = P/9 at equilibrium and P is total pressure, the ratio of Kp/P is equal to (The ones marked in blue, those steps I couldn't understand , please explain it ) Share with your friends Share 70 Vartika Jain answered this Dear User, Here the initial pressure of the system is taken as Pinitial. Now, 2NOBr ↔ 2NO + Br2Initial pressure Pinitial 0 0At equilibrium Pinitial(1-2α ) 2Pinitialα PinitialαHere 2α is used for NOBr because the rate of decomposition is multiplied by the stoicheometric coefficient. Pressure at equilibrium of NO is also multiplied by 2 as the formation of NO is also multiplied by the stoicheometric coeficient.Total pressure at equilibrium, P = Pinitial (1-2α) + 2Pinitialα+ Pinitialαor, P = Pinitial (1+α)Now, we have calculated that Pinitial =89P and Pinitialα = P9 (from the step PBr2= Pinitialα = P9)Therefore, Equilibrium pressure of 2NOBr = Pinitial(1-2α ) = Pinitial - 2 PinitialαSubstituting the values of Pinitial and Pinitialα, we getEquilibrium pressure of 2NOBr = 89P - 2×P9=69P 1 View Full Answer