for what value of x {x=x^2;x belongs to R}
for that your answer is
We have, x 2 = x ⇒ x 2 - x = 0 ⇒ x ( x - 1) = 0 ⇒ x = 0 or 1
So there are two values of x that is 0 and 1 as both of them belongs to R
What if we take 1=x/x^2 and if we substitute x=0 then it becomes 1/0 which is undefined.
Please explain why x=0
The equation x2 = x is considered as an quadratic equation, which is simplified by the method given below
x2 = x ⇒ x2 - x = 0 ⇒ x (x - 1) = 0 ⇒ x = 0 or x = 1