for what value of x {x=x^2;x belongs to R}

for that your answer is

 We have,   x   =   x    x   -   x   = 0 ⇒   x ( - 1) = 0 ⇒  x   = 0 or 1

So there are two values of that is 0 and 1 as both of them belongs to R

 

What if we take 1=x/x^2 and if we substitute x=0 then it becomes 1/0 which is  undefined.

Please explain why x=0

The equation x2 = x is considered as an quadratic equation, which is simplified by the method given below

 x2 = x ⇒ x2 - x = 0 ⇒ x (x - 1) = 0 ⇒ x = 0 or x = 1

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