For what values of k,the numbers ... 1+k,5/6 + k,13/18 + k are in G.P.

by using b2=ac u can solve the prblm here b=5/6+k,a=1+k,c=13/18+k

  • 0

(5/6 + k)2 = (1+k ) (13/18 +k )

25 /36 + k2 + 10 /6 k = 13/18 + k + 13/18 k + k2

13/18 k + k - 10/6 k = 25/36 -13/18

k / 18 = - 1/36

 k = - 1/2

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