Given a triangle with side AB= 8 cm . To get a line segment of AB' = 3/4 of AB , it is required to divide the line segment AB in the ratio :
(A) 3:4

(B) 4:3

(C) 1:3

(D) 3:1

AB is the line segment. AB = 8 cm.

In order of locate B' on AB such that AB' = (3/4) AB, divide the line segment AB in the ratio 3: 4.

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