GIVEN THAT TAN X=12/5,COS Y=-3/5 AND THAT ANGLE X AND Y ARE IN THE SAME QUADRANT. WITHOUT USING TABLES FIND THE VALUE OF 
(i)SIN (X+Y)       (ii)COS Y/2

Dear Student ,
Please find below the solution to the asked query :

tan x=125 , cos y=-35tan is positive and cos is negative , So x and y will lie in third quadrant .tan x=125=PBH=P2+B2=144+25=13sin x=PH=-1213     Sin x is negative in third quadrantcos x=BH=-513     Cos x is negative in third quadrantcos y=BH=-35P=H2-B2=25-9=4sin y=PH=-45     Sin y is negative in third quadrant1 sinx+y=sin x cos y + cos x sin y=-1213-35+-513-45=3665+2065=5665   ANS...2 cos y2=-1+cos y2  as π<y<3π2, then π2<y<3π4 =-1-352=-5-352=-15   ANS...
 
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