Given the mass of iron nucleus as 55.85u and A= 56, find the nuclear density?

according to rutherford's relationsradius of nucleus = ro×A13 ro = constant = 1.2×10-15 mtherefore r = 1.2×10-15 ×563r = 4.59 ×10-15 malso,1u = 1.67×10-27 kg55.85 u = 9.327 ×10-26 kg = mass of nucleus of iron atomnuclear density = mass of nucleus of iron atomvolume of nucleus nuclear density = 9.327 ×10-26 kg43π×r3 =9.327 ×10-26 kg43π×4.59 ×10-15 3nuclear density = 4.851×1018 kg/m3

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