Help in the following

Solution:
Resistive force acting on the bike of mass 100 kg,
 $F=\left(100 \mathrm{Kg}\right)\times \left(2 \mathrm{N}/\mathrm{kg}\right)=200 \mathrm{N}$
Velocity of the bike, v = 4 m/s
So, power of the bike,
$p=F\times v=200\times 4=800 \mathrm{W}$
Hence, the correct answer is option (2).