Help me find the answer please
It is given that PA and PB are tangents to the given circle.
∴∠PAO=90° (Radius is perpendicular to the tangent at the point of contact.)
OB = OA (Radii of the circle)
∴∠OAB=∠OBA=40° (Angles opposite to equal sides are equal.)
∠AOB+∠OAB+∠OBA=180° (Angle sum property)