Here is an octagonal spinner (Fig A). 1, 2, 3, 4, 5, 6, 7, and 8 are 
marked on it. Write the probabilities of occurrence of the following 

a Spinner lands on 4. P(4) = 
b Spinner lands on an even number. P(even) 
c Spinner lands on ten. P(10) = 
d Spinner lands on a number less than 4. 
P(less than 4) = 
e P(less than 9) = 
f P(3 to 6)- 

Dear Student,
Probability=Favourable number of outcomesTotal number of outcomes
In the given question, Since there are  8 possibilities when we spin the wheel, Total no. of outcomes=8
(a)Favourable no. of outcomes = 1 (Since only one portion is marked 4)
(b)Favourable no. of outcomes = 4 (Since there are four portions marked with an even number , namely, 2,4,6,8)

(c)Favourable no. of outcomes=0 (Since there is no potion marked with 10)
(d)Favourable no. of outcomes= 3 (Since there are 3 numbers less than 4 namely 1,2,3)

P(less than 4)=38
(e)Favourable no. of outcomes=8 (Since all numbers are less than 9)
P(less than 9)=88=1
(f) Favourable no. of outcomes=4 (i.e. 3,4,5,6)
P(3 to 6)=48=12

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