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Here is an octagonal spinner (Fig A). 1, 2, 3, 4, 5, 6, 7, and 8 are

marked on it. Write the probabilities of occurrence of the following

events.

a Spinner lands on 4. P(4) =

b Spinner lands on an even number. P(even)

c Spinner lands on ten. P(10) =

d Spinner lands on a number less than 4.

P(less than 4) =

e P(less than 9) =

f P(3 to 6)-

$Probability=\frac{Favourablenumberofoutcomes}{Totalnumberofoutcomes}$

In the given question, Since there are 8 possibilities when we spin the wheel, Total no. of outcomes=8

(a)Favourable no. of outcomes = 1 (Since only one portion is marked 4)

$\Rightarrow P\left(4\right)=\frac{1}{8}\phantom{\rule{0ex}{0ex}}$

(b)Favourable no. of outcomes = 4 (Since there are four portions marked with an even number , namely, 2,4,6,8)

$\Rightarrow P\left(even\right)=\frac{4}{8}=\frac{1}{2}$

(c)Favourable no. of outcomes=0 (Since there is no potion marked with 10)

$\Rightarrow P\left(10\right)=\frac{0}{8}=0$

(d)Favourable no. of outcomes= 3 (Since there are 3 numbers less than 4 namely 1,2,3)

$\Rightarrow P(lessthan4)=\frac{3}{8}$

(e)Favourable no. of outcomes=8 (Since all numbers are less than 9)

$\Rightarrow P(lessthan9)=\frac{8}{8}=1$

(f) Favourable no. of outcomes=4 (i.e. 3,4,5,6)

$\Rightarrow P(3to6)=\frac{4}{8}=\frac{1}{2}$

Regards

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