How can we solve this equation:-
3x(7x-4)=(5x-2)(3x+4)
3x(7x-4) = (5x-2)(3x+4)
Expand the both sides :
3x(7x-4) = 5x(3x+4) - 2 (3x+4)
21x2 - 12x = 15x2+ 20x - 6x -8
(21x2 - 15x2) + ( -12x-20x+6x) + 8 = 0
6x2 - 26x +8 = 0
Dividing both sides by "2"
3x2 - 13x + 4 = 0
By splitting the middle term :
3x2 - 1x-12x + 4 = 0
x(3x-1) -4(3x-1) = 0
(x-4) (3x-1) = 0
x-4 = 0 and 3x-1 = 0
x=4 and x = 1/3
The value of x = 4 , 1/3
If you are satisfied do give thumbs up.