How do you find the slope of the line perpendicular to the line joining the points (2,5) and (-3,6) ?

Given points are (2, 5) and (-3, 6).

So, the equation of the line joining the points (2, 5) and (-3, 6) is:

 

On comparing (1) with y = mx + c , we get

 slope of the line (1) = m1

Now, we have to find the slope of the line which is perpendicular to the line joining the points (2, 5) and (-3, 6).

Let its slope be m2.

We know that, when two lines are perpendicular to each other, the product of their slope is equal to -1.

Therefore, m1 × m2 = -1

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I think the concepts of straight lines are not clear to u. 

Its simple find the equation of the line joining the 2 given points. I think u know how to find the equn. of line joining 2 points then find the slope of the line using m1=-A//B. Since the line is prependicular to it. Therefore the slope of prependicular line would be m2=B/A

Sarsiz Chauhan

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