How do you find the slope of the line perpendicular to the line joining the points (2,5) and (-3,6) ?

**Given** points are (2, 5) and (-3, 6).

So, the equation of the line joining the points (2, 5) and (-3, 6) is:

On comparing (1) with y = mx + c , we get

slope of the line (1) = m_{1}

Now, we have to find the slope of the line which is perpendicular to the line joining the points (2, 5) and (-3, 6).

Let its slope be m_{2}.

We know that, when two lines are perpendicular to each other, the product of their slope is equal to -1.

Therefore, m_{1} × m_{2} = -1

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