How does kinetic energy change if momentum is increased by 3times?
Solution
We know,
KE = ½ mv2
P = mv
Therefore, KE = ½ (mv)2/m = p2/(2m)
Considering the mass to be constant, if the momentum is increased by 3 times, the new momentum be,
P/ = 3P
The new kinetic energy is, KE/ = (P/)2/(2m)
=> KE/ = (32)[P2/(2m)] = 9 KE
So kinetic energy becomes 9 times