# how many numbers greater than 1000000 can be formed by using the digits 1,2,0,2,4,2,4?

Since, 1000000 is a 7-digit number and the number of digits to be used is also
7. Therefore, the numbers to be counted will be 7-digit only. Also, the numbers have to
be greater than 1000000, so they can begin either with 1, 2 or 4.
The number of numbers beginning with 1 =
6! 4 5 6
3! 2! 2
× ×
= = 60, as when 1 is
fixed at the extreme left position, the remaining digits to be rearranged will be 0, 2, 2, 2,
4, 4, in which there are 3, 2s and 2, 4s.
Total numbers begining with 2
= 6! 3 4 5 6
2! 2! 2
× × ×
= = 180
and total numbers begining with 4
6! 4 5 6
3!
= = × × = 120

• -4

Given, digits are 1,2,0,2,4,2 and 4.

So, now we have to find the numbers greater than 1000000

In a 7-digit number, 0 can't appear in the ten lac's place. So, ten lac's place can be filled in 6 ways.

Since repetition of digits isn't allowed and 0 can be used at lac's place, so lac place an be filled again in 6 ways.

Similarly, ten thousand's place, thousand's place, hundred's place, ten's and one's place can be filled in 5, 4, 3, 2 and 1 ways respectively.

Now, in the given digits the digit 2 is repeating thrice whereas the digit 4 is repeating twice.

Hence, the required 7-digit numbers formed

• 39

Wow! 2 students 2 different answers. Fine.

Experts please see to this hep giving the correct answer which may not be above.

thanx.

• 3

let the number be x.

x10,00,000.

digits we are allowed to use are 1,0,2,2,4,2,4.

there are 7 numbers and we can arrange them in 7! ways:

7*6*5*4*3*2*1.

since we are not allowed to repeat the numbers and 4 is repeated twice and 2 is repeated thrice,we he to divide it by 3! and 2!v(4arranged in 2! ways and 2 arranged in 3! ways)

=7*6*5*4*3*2*1/3*2*1*2*1

=210*2

=420.

but since this number has to greater than 10,00,000;

the first number cannot be 0.

now we are left with 6 numbers we can choose from and these can be arranged in 6! ways:

6*5*4*3*2*1.

since repetion not allowed: 2!*3!(same reason).

=6*5*4*3*2*1/3*2*1*2*1;

=60.

therefore,the no.of numbers greater then 10,00,000 is

=(7!/2!*3!)-6!/2!*3!)

=420-60

=360.

Therefore there are 360 numbers greater then 10,00,000.

hope it helps :) cheers!

• 18

it is x10,00,000....

not x10,00,000

• -2
According to the question, the no.s will be 7-digit no.s. Out of the given no.s, 0 cannot be placed at the tenlakh's place, hence, it will be filled in 6 ways.
If the repitition is allowed, then the further places would be filled in 7 ways each. So the total no. of ways would be 6?7?7?7?7?7?7.
If the repitition is not allowed, then the total no. of ways would be 6?6!
• -3
If number is greater than 1000000 it must be starts from 1,2and4 (in case of 7 digit number) If number starts with 1, remaining 6 digit can be filled from 6 numbers namely 0,2,2,2,4,4 6!/(2!3!) = 60 If number starts with 2, the remaining numbers 0,1,2,2,4,4 should be filled at 6 remaining place 6!/(2!2!) = 180 And last if number starts with 4, the remaining numbers 0,1,2,2,2,4 will take place in 6!(1!3!) = 120 ways Total number of ways is 60+180+120 = 360 ways
• 1
If number is greater than 1000000 it must be starts from 1,2and4 (in case of 7 digit number) . If number starts with 1, remaining 6 digit can be filled from 6 numbers namely 0,2,2,2,4,4 6!/(2!3!) = 60 . If number starts with 2, the remaining numbers 0,1,2,2,4,4 should be filled at 6 remaining place 6!/(2!2!) = 180 . And last if number starts with 4, the remaining numbers 0,1,2,2,2,4 will take place in 6!(1!3!) = 120 ways . Total number of ways is 60+180+120 = 360 ways
• -4

• 4
hahahahhha
• -4
6*6*5*4*3*2*1 = 4320
• -1
This us the solution.....

• 1
As we have to find no. Greater than 4 lacs which can be domed using 0,2,2,4,4 and 5
SO No. Of possibilities of filling 1st digit is 3 as we want no. Greater than 400000 and then 5!
Therefore no of possibilities is (3 × 5!)/2!2! as 4 and 2 is repeated twice each.
And we have not taken repetition in this case otherwise it would have been infinite.
• 1
12024245
• 0
The right answer is 360
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It has 7 digits to form a number
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IT HAS 7 DIGITS TO FORM.A NUMBER
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TgutbyHbz cGEr7k d8phby3mdh
• -1
According to me meaning of them can be formed which are given below....
- 2224410
- 2244101
- 4422201
- 2244201
- 1044222
- 1022244
- 1024422
- 1022442
- 1202442
- 1220442
- 1224042
- 1224402
- 1224420
........

And so on it goes you can form more numbers by replacing zero in each number and changing the format of the 1 ,2 ,0,4, 2,4...
I hope my answer helped you..
Yes please give it a upvote I will feel very happy that you like my answer...
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word meaning
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