How many rectangles can be drawn with 24 cm as perimeter when the sides are posetive integers in centimeters?? PLZZZ REPLY FAST MY EXAM IS CUM9
Let the length and breadth of the rectangle be l and b respectively.
Given: Perimeter of rectangle = 24 cm
∴ 2 (l + b) = 24 cm
⇒ l + b = 12 cm
S.No. | Length (l) | Breadth (b) | Length + Breadth = l + b |
1 | 11 | 1 | 12 |
2 | 10 | 2 | 12 |
3 | 9 | 3 | 12 |
4 | 8 | 4 | 12 |
5 | 7 | 5 | 12 |
6 | 6 | 6 | 12 |
7 | 5 | 7 | 12 |
8 | 4 | 8 | 12 |
9 | 3 | 9 | 12 |
10 | 2 | 10 | 12 |
11 | 1 | 11 | 12 |
So, clearly there are 11 combination of length and breadth possible, by using these combinations we can draw 11 types of rectangles.