HOw many terms are there in the AP : 2,9,16,...........,261

since, a = 2 ,d = 9-2 = 7 and an(last term) = 261

so, 261= 2 +(n-1)x7

261-2= (n-1)7

259/7=n-1

37=n-1

n=38

therefore, no. of terms are 38

  • 2

Given

a = 2

d = 7

l = 261

n = ?

= a + (n - 1) d = l

= n = l - a/d + 1

= n = 261 - 2 /7 + 1

= n = 259/7 + 1

= n = 37 +1

= n = 38 //

there fore its the 38 th term

  • 0
What are you looking for?