how much alluminium sheet will be required to make a container with lid whose length is 13m, breadth is 8m, and height is 4m?

Lenght of the container = 13m

Breadth of the container = 8m

height of the container = 4m

T.S.A of the container = 2(lh + bh + lb)

= 2(13 x 4 + 8 x 4 + 13 x 8)

= 2( 52 + 32 + 104)

= 2 x 188

= 376m2

  • 1

amount of aluminium required = total surface are of cuboid

= 2 (lb + bh + lh)

= 2 (13*8 + 8*4 + 4*13)

= 2 (188)

=375 m 2

  • 0

If it is in the shape of Cuboid Then it is :

L= 13

B = 8

H= 4

TSA OF CUBOID IS :2(lb+bh+hl)

So 2(13*8+8*4+4*13)

we get , 2(104+32+52)

2(188)

TSA OF CUBOID WILL BE =376m2

Al used required to make container with lid will be 376m2

  • 3
What are you looking for?