how much marble of 96.5% purity would be required to prepare hundred litres of carbon dioxide at STP when marble is acted upon by dilute HCl so in this i didnt understand the last step why we divided it with 96.5%

how much marble of 96.5% purity would be required to prepare hundred litres of carbon dioxide at STP when marble is acted upon by dilute HCl so in this i didnt understand the last step why we divided it with 96.5% C02 91 062. Cacog + caC12 + H20 + 22.4L at 100 g N.T.P. 22.4 L of C02 at N.T.P. is obtained from CaC03 = 100g 100 L of C02 at N.T.P. will be obtained from CaC03 100 = —x 100 = 446.4 g 22.4 446.4 x 100 mpure marble required = 462.6 g• 96.5 0 63.CH4 + 202

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