How ( SiH3 )2O takes part in back bonding and why P(CH3) 3 doesn't take part in back bonding?

Dear User,
Si has a vacant d orbital which can take part in back bonding, however C does not have a d orbital and not even an empty p orbital to accept back the lone pair of electrons therefore it does not take part in back bonding.
Electronic configuration of Si =  3s2 3p‚Äč4 3d0
Electronic configuration of C = 2s2 2p4
Therefore, (SiH3)2O takes part in back bonding while P(CH3)3 does not.

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