How to solve this question? The given solution is not even a bit helpful!

46 .   I f   α ,   x   a r e   r e a l   n u m b e r   a n d   | a |   <   1 ,   | x |   <   1 ,   t h e n   1   +   ( 1   +   α ) x   +   ( 1   + α   +   α 2 ) x 2   +   . .   . . .   i s   e q u a l   t o ( a ) 1 1 - α 1 - α x                               ( b ) 1 1 - α 1 - x   ( c )   1 1 - x 1 - α x                           ( d ) 1 1 + x α 1 - α

Dear Student,
Please find below the solution to the asked query:

We haveS=1+1+ax+1+a+a2x2+1+a+a2+a3x3+....=1+x+ax+x2+ax2+a2x2+x3+ax3+a2x3+a3x3+....=1+x+x2+..+ax+ax2+ax3+...+a2x2+a2x3+...+....All brackets are G.P. of infinite terms with common ratio x and first term 1,ax,a2x2,... respectively.Sum=First Term1-Common RatioS=11-x+ax1-x+a2x21-x+....=11-x1+ax+a2x2+...... which is again G.P.=11-x11-ax..OptionC

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