H o w d i d 4 c o t θ × 9 t a n θ b e c o m e 36 1 t a n θ × t a n θ : ⇒ h 4 = c o t θ ⇒ h = 4 c o t θ I n △ A B Q , A B Q B = tan θ h 9 = tan θ h = 9 tan θ F r o m e q u a t i o n ( i ) a n d ( i i ) , w e g e t h × h = 4 c o t θ × 9 tan θ ⇒ h 2 = 36 c o t θ × tan θ = 36 1 tan θ × tan θ ⇒ h 2 = 36 ⇒ h = 6 m . Share with your friends Share 0 Lovina Kansal answered this Dear student We have,h×h=4cotθ×9tanθ⇒h2=36 cotθ tanθ⇒h2=36×1tanθ×tanθ ∵cotx=1tanx⇒h2=36⇒h=6 or h=-6 rejected ∵height cannot be negative Regards 1 View Full Answer