I need the answer of the 5th question but u can also answer the rest of the questions if u want

2/x + 2/3y = 1/6
2/x + ( 2/y ) × 1/3 = 1/6 ---( 1 )
3/x + 2/y = 0
2/y = - 3/ x ------( 2 )
Put ( 2 ) in equation ( 1 ) ,
2 / x + ( - 3 / x ) × 1/3 = 1/6
2/x - 1/x = 1/6
1 / x = = 1/6
x = 6 ----( 3 )
Put ( 3 ) in equation ( 2 ),
2 / y = ( - 3 / 6 )
2/y = - 1/2
1 / y = - 1 / 4
y = - 4
Therefore ,
x = 6 ,
y = - 4
I hope this helps you.:)