# i want area and perimerter of minor ,major segment,quaderent ,semi circle and sector

If the radius of the circle = r and the chord is r, then,

the perimeter of the minor segment = r+(π/3)r = r[1+(π/3)].

The perimeter of the major segment = r[1+(5π/3)].

The formula to find the area of minor segment is r

^{2}(θπ/180 - sinθ)/2.

Area of major segment = area of triangle + 3/4 area of circle

= 1/2 height × base + 3/4 πr²

= 1/2 × r × r + 3/4πr²

= r²/4( 2 + 3π)

Area of Segment = (

*θ ×*

*π/*

**360**−

*sin(θ)/*

**2**) × r

^{2}

Area of a quadrant, A= (π*r^{2})/4.

Perimeter of semicircle = πr+2r and area of semi circle = πr^{2}/2.

**area**of a

**sector**of a circle is ½ r² ∅, where r is the radius and ∅ the angle in radians subtended by the arc at the centre of the circle.

Perimeter of the sector = L + 2r

L - length of sector

r - radius

Regards

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