I want the answer which is above exercise10.4 ... With figure

Dear Student,

Please find below the solution to the asked query:

We follow these steps to construct Triangle ABC from given formation  .

Step 1 :  Draw a line AB = 5.8 cm

Step 2 :  Now take any radius ( Less than half of AB ) and take center  " A "  draw an arc that intersect our line AB at  " P " , With same radius and center is " P "  draw another arc that intersect our previous arc at "  Q " .

Step 3 :  Draw a line AQ and extend it  to R . So ,  $\angle$ BAR  = 60$°$

Step 4 :  Now take any radius ( Less than half of AB ) and take center  " B "  draw an arc that intersect our line AB at  " S " , With same radius and center is " S "  draw another arc that intersect our previous arc at "  T "  .

Step 5 :  With same radius and take center " S " and " T  "  we draw two arcs that intersect at " X  " . Now join BX and extend it to Y AS :   $\angle$ ABY  = 30$°$ .

Line AR and BY intersect at  " C " . as we get triangle ABC .


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