If 1.4 gram of Calcium oxide is formed by the complete decomposition of CaCO3,then amount of CaCO3 taken and amount of CO2 formed respectively

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Solution:

Please find below the solution to the asked query.

The reaction is:
$CaC{O}_3 \rightleftharpoons CaO + C{O}_2$
Molar mass of CaO = 56 g/mol
Molar mass of CaCO_​3 = 100 g/mol
Molar mass of CO₂ = 44 g/mol
This equation says that
56 g of CaO is formed completely by decomposition of = 100 g of CaCO₃
So, 1.4 g ​of CaO will be formed completely by decomposition of = $\frac{100 g of CaC{O}_3}{56 g}\times 1.4 g = 2.5 g of CaC{O}_3$

Similarly, 100 g of CaCO_​3 decomposes to give = 44 g of CO₂
So, 2.5 g of CaCO₃ will decompose to give = $\frac{44 g of C{O}_2}{100 g}\times 2.5 g = 1.1 g of C{O}_2$