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If 1 is zero of the polynomial p(x) = ax2 - 3(a-1)x - 1, then the value of 'a' is

One of the zeroes of the polynomial is 1 .

i.e. when x = 1 p(x) = 0

Let's put  the value of x in the given polynomial

we get ,  a(1)2 -3(a - 1)1 - 1 = 0

  a - 3a +3 -1  = 0

  -2a +2 =0

  a = -2 / -2

   a = 1

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i think the answer is 1

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