let the no be x
then 3/5 of that no =3/5x
and 2/7 of that no =2/7x
if 3/5 exceeds 2/7 by 44 then
3/5x + 44 = 2/7x
3/5x - 2/7x = -44
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Let the no be =x
according to the question 3/5th of a no exceeds its 2/7th by 44 so the equation would be like 3/5th of x=(2/7x)+44
3/5th of x=(2/7th of x)+44
3/5th of x - 2/7 of x=44
LCM of 7 &5=35
21x/35 - 10x/35=44
11x/35=44
11x=44*35
11x=1540
x=1540/11
x=140
hope that this answer helps you.
according to the question 3/5th of a no exceeds its 2/7th by 44 so the equation would be like 3/5th of x=(2/7x)+44
3/5th of x=(2/7th of x)+44
3/5th of x - 2/7 of x=44
LCM of 7 &5=35
21x/35 - 10x/35=44
11x/35=44
11x=44*35
11x=1540
x=1540/11
x=140
hope that this answer helps you.
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the organisers of an essay competition decide that winner in the competition Kehte price of rate 100 and a participant who does not win gets a price of rate 25 the total prize money distributed is 3000 find the number of winners if the total number of participants is 63
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