let the no be **x**

then 3/5 of that no =3/5x

and 2/7 of that no =2/7x

if 3/5 exceeds 2/7 by 44 then

3/5x + 44 = 2/7x

3/5x - 2/7x = -44

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Let the no be =x

according to the question 3/5th of a no exceeds its 2/7th by 44 so the equation would be like 3/5th of x=(2/7x)+44

3/5th of x=(2/7th of x)+44

3/5th of x - 2/7 of x=44

LCM of 7 &5=35

21x/35 - 10x/35=44

11x/35=44

11x=44*35

11x=1540

x=1540/11

x=140

hope that this answer helps you.

according to the question 3/5th of a no exceeds its 2/7th by 44 so the equation would be like 3/5th of x=(2/7x)+44

3/5th of x=(2/7th of x)+44

3/5th of x - 2/7 of x=44

LCM of 7 &5=35

21x/35 - 10x/35=44

11x/35=44

11x=44*35

11x=1540

x=1540/11

x=140

hope that this answer helps you.

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the organisers of an essay competition decide that winner in the competition Kehte price of rate 100 and a participant who does not win gets a price of rate 25 the total prize money distributed is 3000 find the number of winners if the total number of participants is 63

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