if 3x+k,2x+9 and x+13 are three consecutive terms of an AP.,Find k.

=>(2x+9)-(3x+k)=(x+13)-(2x+9)

=>2x-3x+9-k=x-2x+13-9

=>-x+9-k=-x+4

=>9-k=4

=>-k=4-9

=>-k=-5

=>k=5 ans.

hope u understand 

  • 11

since the common difference is equal

2x+9-3x-k=x+13-2x-9

9-x-k=-x+4

9-k=4

-k=-5

k=5

  • 5

thank u buddies

  • 0
What are you looking for?