If 4i+2p/3 j+pk is parallel to the vector i+2j+3k, find p.

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Please find below the solution to the asked query:

We have:a=4i^+2p3j^+pk^b=i^+2j^+3k^As given vectors are parallel, hence they can be written as:a=λb, where λ is constant.4i^+2p3j^+pk^=λi^+2j^+3k^4i^+2p3j^+pk^=λi^+2λj^+3λk^On comparing respective coefficients, we get:4=λ2p3=2λp=3λPut λ=4p=12which should satisify equation obtained by comapring coefficient of k^.Comparing coefficient of k^, we getp=3λ=3×4=12 which is already obtained.Hence  p=12 

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