If a constant torque of 500Nm turns a wheel of moment of inertia 100kgm2 about an axis through it's centre,find gain in angular velocity in 2s.

Given,Torque, τ=500 NmMoment of inertia, I=100 kg m2Now,τ=Iαα=τI=500100=5 rad s-2Gain in angular velocity, ω=αtω=5×2=10 rad s-1

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