if a magnet is suspended at an angle 30 degree to the magnetic meridian the dip needle makes angle of - Physics - Magnetism And Matter

Question

if a magnet is suspended at an angle 30 degree to the magnetic
meridian the dip needle makes angle of 45 degree with the
horizontal the real dip is ??

Panchali Dutta · Accepted Answer

Magnet makes an angle of 30 degree with magnetic meridian.

Apparent horizontal component, B_H' = B_H cos30 = $\frac{\sqrt{3}}{2} B_{H}$

$\tan δ' = \frac{B_{v}}{{B'}_{H}} = \frac{2 B_{v}}{\sqrt{3} B_{H}} \tan 45 = \frac{2}{\sqrt{3}} \tan δ \tan δ = \frac{\sqrt{3}}{2}$

δ = 40.89^o

if a magnet is suspended at an angle 30 degree to the magnetic meridian the dip needle makes angle of 45 degree with the horizontal. the real dip is ??