If a1/3 + b1/3 + c1/3 = 0 then
a) a+b+c=0
b) (a+b+c)3=27abc
c) a+b+c=3abc
d) a3+b3+c3=0
Also explain how ??
a1/3+ b 1/3 + c 1/3 = 0
( a1/3 + b1/3) = -c1/3
( a1/3 + b1/3)3 = ( - c1/3 )3
( a1/3 )3 + ( b 1/3)3 + 3 a1/3 . b.1/3 ( a 1/3 + b1/3 ) = - c
a + b + c + 3 a 1/3 b 1/3 ( - c 1/3 ) = 0
( a + b + c ) = 3 a 1/3 b 1/3 c 1/3
( a + b + c )3 = ( 3 a 1/3 b 1/3 c 1/3) 3
( a + b + c )3 = 27 abc