If ABCD is a parallelogram, and X and Y be any two points on DC and AD respectively. Show that the triangle AXB and BYC are equal in area.

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Please find below the solution to the asked query:

Since AXB and parallelogram ABCD have same base AB and between same parallels AB and DC, thenarea of AXB = 12area of gm ABCD    ....1Since BYC and parallelogram ABCD have same base BCand between same parallels BC and AD, thenarea of BYC = 12area of gm ABCD    ....2from 1 and 2, we getarea of AXB  = area of BYC 

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