If alpha beta are roots of the polynomial f(x) = x2-px+q then Find value of

1) alpha2 + beta2

2) 1/alpha + 1/beta

3) alpha/beta + beta/alpha

Given quadratic x2 - px + q

Sum of roots = α+β = p

Product of roots = αβ = q

1) (α+β)2 = α2 + β2 + 2αβ

α2 + β2 = (α+β)2 - 2αβ

α2 + β2 = p2 - 2q

-

2) 1/α + 1/β = (α + β) / αβ

1/α + 1/β = p / q

-

3)β/α + α/β = (α2 + β2) / αβ

We have proved above

α2 + β2 = p2 - 2q

β/α + α/β = (p2 - 2q )/q

β/α + α/β = p2/q - 2

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f(x) = x2 - px + q

Here a = 1, b = -p and c = q

α + β = -b/a = -(-p)/1 = p

αβ = c/a = q/1 = q

(1) α2 + β2 = (α + β)2 - 2αβ

= p2 - 2q

(2) 1/α + 1/β = α + β / αβ

= p/q

(3) α/β + β/α = α2 + β2 / αβ

= p2 - 2q / q

= p2/q - 2

  • 10
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