If an electric iron of 1600 W is used for 45 minutes everyday, find the elcetric energy consumed in the month of March.

power of electric iron =1600w
=1.6kw
time=45min.
=0.75hr
energy=power*time taken
=1.6*0.75
=1.2kwhr

It is used for month of march
march has 31 days
therefore, the energy used for 31 days=1.2*31
=37.2kwhr
 

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1600 W = 1600 / 1000 = 1.6 kWh
45 minutes = 45/60 = 0.75 
Energy =  1.6 kWh *  0.75 = 1.2 Joule
energ consume in the month of march = 31 * 1.2 
= 36 JOule
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