if d is the HCF of 45&27,find x,y satisfying d=27x+45y. Share with your friends Share 27 Lalit Mehra answered this Dear Student!Cheers! 81 View Full Answer Suspense answered this if d is hcf of 45 & 27 find x,y satisfying d = 27x+45yhcf of 45 and 27 = 9d = 27x+45y=> 9 = 27x+45y=> 1= 3x + 5y=> 3x + 5y-1=0there are infinite solutions,one ans is, -3,2 -12 Sruti .b.s answered this 45=27 X 1 +1827=18 X 1 + 918 = 9 X 2 +0HCF is 918=45(1)-27(1)9X2=45(1)-27(1)9 = 45(1/2)-27(1/2)=> 27(-1/2)+45(1/2)=9thereforex= -1/2 and y=1/2HOPE THIS HELPS YOU -11
