if in a gp the (p+q)th term is a and (p-q)th term is b , prove that the pth term is sqrt (ab).

@Ranjeeta Yadav has found equations (1) and (2) correctly.

On multiplying both the equations, we get

 

Hence, the pth term of the GP is .

  • 51

Heyyy..m nt getting watz sqrt heree..bt i cn gve as much sol. as i knww..see

Tp+q = ARp+q-1   = a ___(1)

Tp-q = ARp-q-1   =b______(2)

Dividing 1 by 2..

Rp+q-1-p+q+1 = a/b

R2q =a/b

Rq = (a/b)2  ______(3)

Now , Tp = ARp-1

we can write it as , ARp+q-1/Rq

Now , from (1) & (3)

a/(a/b)2 = b2/a...

hope ths helpss...:)

  • -19
What are you looking for?