if k-1 , k+3 , 3k-1 are in A.P. THEN FIND THE VALUE OF K Share with your friends Share 7 Varun.Rawat answered this Let t1 = k-1; t2 = k+3; t3 = 3k-1Since, t1, t2 and t3 are in AP, then t2 - t1 = t3 - t2⇒k+3 - k-1 = 3k-1 - k+3⇒k+3-k+1 = 3k-1-k-3⇒4 = 2k - 4⇒2k = 4 + 4⇒2k = 8⇒k = 82 = 4 9 View Full Answer Deepa Dharshini answered this Please find this answer -4 Pranay answered this k= -2 -3