if k-1 , k+3 , 3k-1 are in A.P. THEN FIND THE VALUE OF K

Let t1 = k-1; t2 = k+3; t3 = 3k-1Since, t1, t2 and t3 are in AP, then    t2 - t1 = t3 - t2k+3 - k-1 = 3k-1 - k+3k+3-k+1 = 3k-1-k-34 = 2k - 42k = 4 + 42k = 8k = 82 = 4

  • 9
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  • -4
k= -2
  • -3
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