if log0.3(x-1) < log0.09(x-1), then x lies in the interval.... Share with your friends Share 3 Kavita answered this AAYUSH,....THANKS FOR YOUR EFFORT BUT THE SOLUTION IS WRONG........ 6 View Full Answer Manali Sangani answered this log0.3 (x-1) < log0.09 (x-1)log0.3 (x-1) < log(0.3)^2 (x-1) log0.3 (x-1) < 1/2 log0.3 (x-1) 2log0.3 (x-1) < log0.3 (x-1) (x-1)^2>x-1 x>2 (2, infinity) 51 Snigdha Mishra answered this But why the sign of inequality has changed 5 Shreyansh answered this his answer is right there is one more domain that is (x-1)>0 3 Faisal answered this Sign of inquality has changed because base is less than 1 4 Aryan Sharma answered this Wrong answer 😟😟😟😟😟 -3 Golu Kumar answered this Please find this answer 0 Padmapriya Ravi answered this Attached below is the solution. 9 Siddharth Verma answered this Please find this answer 3 Chhavi Bhati answered this Please find this answer 0
