If m = 7777 7777 is a 99 digit number and n =9999 9999 - Maths - Complex Numbers and Quadratic Equations

Question

If m = 7777 7777 is a 99 digit number and n =9999 9999 is a 77
digit number, then the sum of the digits in the product m x n is
:
(a)890
(b)891
(c)892
(d)893
(this question was answered,but the expert answer is wrong, they
gave another answer out of option)

Akshay Kamthan · Accepted Answer

Dear Student,
Please find below the solution to the asked query:

Given, m = 7777
777 upto 99 digits  Similarly, n = 999
 99 upto 77 digits  Here, in the number 7777
777 we had 99 digits and in the number 999
99 we had 77 digits
  Now, product of m × n = 7777
777 × 999
99  Here, the sum of digits in product of 7777
777 × 999
99 will be equal to the sum of respective number of digits in the given number, i
e
,  sum of digits = 99 + 77 =  176  Now, if we multiply (7777
777) with (999
99) we will definitely get 176 digits in the product

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If m = 7777....7777 is a 99 digit number and n =9999....9999 is a 77 digit number, then the sum of the digits in the product m x n is : (a)890 (b)891 (c)892 (d)893 (this question was answered,but the expert answer is wrong, they gave another answer out of option)

If m = 7777....7777 is a 99 digit number and n =9999....9999 is a 77 digit number, then the sum of the digits in the product m x n is :
(a)890
(b)891
(c)892
(d)893
(this question was answered,but the expert answer is wrong, they gave another answer out of option)