if o is any point in the interior od triangleABC.PROVE OA +OB+OC>1/2(AB+BC+CA)

It is such a easy question --===

- AB < AO + BO ( Sum of 2 sides of triangle is greater than 3)
- AC < AO + CO ( Sum of 2 sides of triangle is greater than 3)
- BC < BO + CO ( Sum of 2 sides of triangle is greater than 3)

NOW ON ADDING LHS AND RHS WE GET -

- AB + AC + BC < AO + BO + AO + CO + BO + CO
- AB + AC + BC < 2AO + 2BO + 2CO
- AB + AC + BC < 2(AO + BO + CO)
- FINAL ANS = 1/2(AB + AC + BC) < AO + BO + CO

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