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If one end of a diameter of a circle x^2 + y^2 -4x-6y+11 =0 is (8, 4) show that coordinate of the other end are (-4, 2).

-4=2g

g=-2

-6=2f

f=-3

center=(-g,-f)

center=(2,3)

let the coordinate of other end of the diameter is x and y then,

2=x+8/2

x=-4

3=y+4/2

y=2

hence proved*