If one in 25 carries a recessive allele what must be the frequency of the homozygous recessive genotype in - Biology - Biological Classification

Question

If one in 25 carries a recessive allele what must be the frequency
of the homozygous recessive genotype in a population at hardy-
Weinberg equilibrium ​

Anjali Pandey · Accepted Answer

Dear Student,

Let the frequency of dominant allele be
p
Let the frequency of recessive allele be
q
also, we know that
p + q = 1

The frequency of recessive allele (q) is
1 in 25 i e 1/25 = 0 04 (given)
therefore ,
p + 0 04 = 1
hence , p = 1 - 0 04 = 0
09

For a population in Hardy - Weinberg equilibrium
p2 + q2 + 2pq = 1

So,
q2 = (0 04)2 = 0 0016
(frequency of homozygous recessive)
p2 = (0 96)2 = 0 9216
(frequency of homozygous dominant)
2pq = 2 x 0 04 x 0 96 = 0 0768 (frequency of
heterozygous)

therefore,
Frequency of homozygous recessive genotype is 0
0016

Regards

If one in 25 carries a recessive allele what must be the frequency of the homozygous recessive genotype in a population at hardy- Weinberg equilibrium.​

If one in 25 carries a recessive allele what must be the frequency of the homozygous recessive genotype in a population at hardy- Weinberg equilibrium.