If one root of quadratic polynomial 2x​​2-3x+p is 3, then find the other root and also find the value of p.(NO LINKS PLZ)

Let px = 2x2 - 3x + pSince, 3 is a root of px, then     p3 = 0232 - 3 × 3 + p = 018 - 9 + p = 0p = -9Now, px = 2x2 - 3x - 9=2x2 - 6x + 3x - 9=2xx - 3 + 3x - 3=2x + 3x - 3Now, roots of px are given by solvingpx = 02x + 3x - 3 = 0x = -32  and x = 3So, the other root = -32

  • 1
What are you looking for?