If p=7a2+5ab-9b2,Q=4b2-3a2-6ab &R=-4a2+ab+5b2 ,prove thatp+q+r=0

Consider p + q + r

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just plug in the values

7a^2 + 5ab - 9b^2 + 4b^2 - 3a^2 - 6ab - 4a^2 + ab + 5b^2 = 0

7a^2 - 3a^2 - 4a^2 -9b^2+4b^2+5b^2+5ab-6ab+ab = 0

7a^2-7a^2-9b^2+9b^2+6ab-6ab = 0

0 = 0

hence proved

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